(7x-3/x+1)-(8/x)=-(2/x^2+x)

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Solution for (7x-3/x+1)-(8/x)=-(2/x^2+x) equation: 



(7x-3/x+1)-(8/x)=-(2/x^2+x)

We move all terms to the left:

(7x-3/x+1)-(8/x)-(-(2/x^2+x))=0



Domain of the equation: x+1)!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x^2+x))!=0

x∈R



We add all the numbers together, and all the variables

(7x-3/x+1)-(+8/x)-(-(2/x^2+x))=0

We get rid of parentheses

7x-3/x-8/x-(-(2/x^2+x))+1=0

We calculate fractions

We do not support expression: x^3

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